x/(-2x^2+6)=1/80

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Solution for x/(-2x^2+6)=1/80 equation:


D( x )

6-2*x^2 = 0

6-2*x^2 = 0

6-2*x^2 = 0

-2*x^2 = -6 // : -2

x^2 = 3

x^2 = 3 // ^ 1/2

abs(x) = 3^(1/2)

x = 3^(1/2) or x = -3^(1/2)

x in (-oo:-3^(1/2)) U (-3^(1/2):3^(1/2)) U (3^(1/2):+oo)

x/(6-2*x^2) = 1/80 // - 1/80

x/(6-2*x^2)-(1/80) = 0

x/(6-2*x^2)-1/80 = 0

(80*x)/(80*(6-2*x^2))+(-1*(6-2*x^2))/(80*(6-2*x^2)) = 0

80*x-1*(6-2*x^2) = 0

2*x^2+80*x-6 = 0

2*x^2+80*x-6 = 0

2*(x^2+40*x-3) = 0

x^2+40*x-3 = 0

DELTA = 40^2-(-3*1*4)

DELTA = 1612

DELTA > 0

x = (1612^(1/2)-40)/(1*2) or x = (-1612^(1/2)-40)/(1*2)

x = (2*403^(1/2)-40)/2 or x = (-2*403^(1/2)-40)/2

2*(x-((-2*403^(1/2)-40)/2))*(x-((2*403^(1/2)-40)/2)) = 0

(2*(x-((-2*403^(1/2)-40)/2))*(x-((2*403^(1/2)-40)/2)))/(80*(6-2*x^2)) = 0

(2*(x-((-2*403^(1/2)-40)/2))*(x-((2*403^(1/2)-40)/2)))/(80*(6-2*x^2)) = 0 // * 80*(6-2*x^2)

2*(x-((-2*403^(1/2)-40)/2))*(x-((2*403^(1/2)-40)/2)) = 0

( x-((-2*403^(1/2)-40)/2) )

x-((-2*403^(1/2)-40)/2) = 0 // + (-2*403^(1/2)-40)/2

x = (-2*403^(1/2)-40)/2

( x-((2*403^(1/2)-40)/2) )

x-((2*403^(1/2)-40)/2) = 0 // + (2*403^(1/2)-40)/2

x = (2*403^(1/2)-40)/2

x in { (-2*403^(1/2)-40)/2, (2*403^(1/2)-40)/2 }

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